Medium
Let's define digit degree of some positive integer as the number of times we need to replace this number with the sum of its digits until we get to a one digit number.
Given an integer, find its digit degree.
Example
- For n = 5, the output should be
digitDegree(n) = 0; - For n = 100, the output should be
digitDegree(n) = 1.
1 + 0 + 0 = 1. - For n = 91, the output should be
digitDegree(n) = 2.
9 + 1 = 10 -> 1 + 0 = 1.
Input/Output
-
[execution time limit] 0.5 seconds (c)
-
[input] integer n
Guaranteed constraints:
5 ≤ n ≤ 10^9. -
[output] integer
[C] Syntax Tips
// Prints help message to the console
// Returns a string
char * helloWorld(char * name) {
char * answer = malloc(strlen(name) + 8);
printf("This prints to the console when you Run Tests");
strcpy(answer, "Hello, ");
strcat(answer, name);
return answer;
}
더보기
Solution
int digitDegree(int n)
{
int count=0;
while(n%10!=n)
{
int N=0;
while(n>0)
{
N+=n%10;
n/=10;
}
n=N;
count++;
}
return count;
}
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