Easy
Determine if the given number is a power of some non-negative integer.
Example
- For n = 125, the output should be
isPower(n) = true; - For n = 72, the output should be
isPower(n) = false.
Input/Output
-
[execution time limit] 0.5 seconds (c)
-
[input] integer n
A positive integer.
Guaranteed constraints:
1 ≤ n ≤ 400. -
[output] boolean
- true if n can be represented in the form a^b (a to the power of b) where a and b are some non-negative integers and b ≥ 2, false otherwise.
[C] Syntax Tips
// Prints help message to the console
// Returns a string
char * helloWorld(char * name) {
char * answer = malloc(strlen(name) + 8);
printf("This prints to the console when you Run Tests");
strcpy(answer, "Hello, ");
strcat(answer, name);
return answer;
}
더보기
Solution
bool isPower(int n)
{
if(n==1)
return true;
for(int i=2;i<=20;i++)
for(int j=2;(int)pow(i,j)<=n;j++)
if((int)pow(i,j)==n)
return true;
return false;
}
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