<Codesignal> Concatenate Arrays

Easy

Given two arrays of integers a and b, obtain the array formed by the elements of a followed by the elements of b.

Example

For a = [2, 2, 1] and b = [10, 11], the output should be
concatenateArrays(a, b) = [2, 2, 1, 10, 11].

Input/Output

• [execution time limit] 0.5 seconds (c)

• [input] array.integer a

  Guaranteed constraints:
  1 ≤ a.length ≤ 10,
  1 ≤ a[i] ≤ 15.

• [input] array.integer b

  Guaranteed constraints:
  0 ≤ b.length ≤ 10,
  1 ≤ b[i] ≤ 15.

• [output] array.integer

[C] Syntax Tips

// Prints help message to the console
// Returns a string
char * helloWorld(char * name) {
    char * answer = malloc(strlen(name) + 8);
    printf("This prints to the console when you Run Tests");
    strcpy(answer, "Hello, ");
    strcat(answer, name);
    return answer;
}

---

Solution

// Arrays are already defined with this interface:
// typedef struct arr_##name {
//   int size;
//   type *arr;
// } arr_##name;
//
// arr_##name alloc_arr_##name(int len) {
//   arr_##name a = {len, len > 0 ? malloc(sizeof(type) * len) : NULL};
//   return a;
// }
//
//
arr_integer concatenateArrays(arr_integer a,arr_integer b)
{
	arr_integer c=alloc_arr_integer(a.size+b.size);

	for(int i=0;i<c.size;i++)
		c.arr[i]=i<a.size?a.arr[i]:b.arr[i-a.size];

	return c;
}